Given two splines, I’ve managed to calculate the length of the vector projection of a onto b (see attached image).
The result is represented by the green square.
The question is: how do I calculate the same result but ALONG the vector b?
Here’s my code
–get the vectors
firstPoint1 = getKnotPoint selection[1] 1 1
secondPoint1 = getKnotPoint selection[1] 1 2
newVec1 = secondPoint1 - firstPoint1
normalizedVector1 = normalize newVec1
firstPoint2 = getKnotPoint selection[2] 1 1
secondPoint2 = getKnotPoint selection[2] 1 2
newVec2 = secondPoint2 - firstPoint2
normalizedVector2 = normalize newVec2
–get the angle between the splines
result = acos (dot normalizedVector1 normalizedVector2)
–get the length of the projection
result2 = (length newVec1)*(cos result)
b = box width:2 length:2 height:2
b.position = [result2,0,0]
I’ve found the solution myself: I needed to multiply that result by the normalized b vector