Linear Perspective : Help With Inclined Planes Using Measuring Point Method

#1

Hi,

i’ve got a question about finding VP of elevation planes using the Measuring Point Method.

I understand that the method for finding VP of inclines planes is to measure from the MP of the respective VP e.g. 35 degrees in this case. where the intersection of the vertical line @ vp Vs the measure angled will be the VP of inclined plane.

In the below example i found 2 VPs and their respective MPs. I also found their inclined VPs, but it seems that although both inclined VPs are at 35 degree elevation to viewer, they seem to be on a different height line, that contracts the theory of the Planes.

Shouldn’t they the inclined VPS be on a common horizontal line which represents 35 degrees elevation from viewer? just like how HL represents all planes with 0 elevation

IVP = ascending vanishing point

Example usage: 2 ramps(not drawn) with one vanishing to Vp1 & the Other to Vp2, with each incline of 35 degrees

Please tell me where is the gap in my knowledge.

Thanks

#2

I find your sketch a little confusing, can you add some more to it to make it a bit more like a finished sketch of some real life objects? For instance, wedge shapes lying on a table.

All I know is, if 2 planes are perfectly parallell to each other in X, Y and Z, one of those directions (in 1 point perspective) will converge. And only one, not two.

#3

Thanks for replying. i already found an answer to that question :slight_smile:

#4

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