View Full Version : fibonacci / golden ratio
48design 01272009, 06:10 PM Hey there,
I'm trying to show the fibonacci spiral onto the viewport but I don't get it.
I handled to display something on the screen but not a spiral...
(
fibonacci_array = #()
gw.setColor #line yellow
for i = 1 to 22 do
(
x = 1.618*i
y = 0.618^i
m = ((xy)/2.2361)
append fibonacci_array ([x,y,0])
)
gw.wPolyline fibonacci_array false
gw.wText ([4,30,0]) "fibonacci spiral" color:yellow
gw.enlargeUpdateRect #whole
gw.updateScreen()
)
Thank You!


ZeBoxx2
01272009, 09:15 PM
that's because you're not actually drawing a spiral, near's I can tell.
myShape = splineshape()
addNewSpline myShape
for p in fibonacci_array do ( addKnot myShape 1 #corner #line p )
updateShape myShape
myShape.vertexTicks = true
Might want to review your code for generating the spiral  if nothing else, the X coordinate shouldn't be a linear progression :)
48design
01272009, 09:42 PM
Thanks for your answer but I need to display this kind of spiral in the view/cameraport
like this one (http://www.learncpp.com/images/CppTutorial/Section7/Fibonacci.png)
Exactly like in this image with rectangles and this spiral...
I started now to make the rectangles "hardcoded" but there must be a formula for this, too... did not find an answer, yet...
maxWidth = gw.getWinSizeX()
maxHeight = gw.getWinSizeY()
gw.setColor #line orange
gw.wPolyline #([0,0,0],[maxWidth*0.618,0,0],[maxWidth*0.618,maxHeight1,0],[0,maxHeight1,0]) true
gw.wPolyline #([maxWidth*0.618,0,0],[maxWidth1,0,0],[maxWidth1,maxHeight*0.618,0],[maxWidth*0.618,maxHeight*0.618,0]) true
48design
01272009, 09:47 PM
adding this line
gw.setColor #line red
gw.wPolyline #([maxWidth1,maxHeight*0.618,0],[maxWidth1,maxHeight1,0],[maxWidth((maxWidth(maxWidth*0.618))*0.618),maxHeight1,0],[maxWidth((maxWidth(maxWidth*0.618))*0.618),maxHeight*0.618,0]) true
makes the next rectangle (number 55 on the image)
I'm not good at math so I can't see a formula... :cry:
Piflik
01272009, 11:07 PM
I wrote a script about the rectangles of a Fibonacci Spiral (not golden ration though...) on [Pixelplausch.de] (http://www.pixelplausch.de/autodesk3dsmax/2658maxscriptvariabelloopdeklarieren.html) . Maybe it helps you..
LoneRobot
01272009, 11:55 PM
you might find this useful too 
http://www.scriptspot.com/3dsmax/goldenguides
48design
01282009, 10:48 AM
Hey, thank you all!
I hope that helps.
;)
48design
01282009, 03:50 PM
I came out with this after trying the link from Piflik. It seems to work in one way or another but for displaying it on the screen/viewport it should be kind of reversed to split the screen like on this image (http://www.learncpp.com/images/CppTutorial/Section7/Fibonacci.png). Any ideas on how to reverse this??
After this change there still is the problem with the spiral but there doesn't seem to be code for this, no curves just polygons and polylines...?
(
global fibonacci_array = #()
maxWidth = gw.getWinSizeX()
maxHeight = gw.getWinSizeY()
global w = 15
global pos_Alt =[0,1,0]  old position
fn drawQuad x y w h =
(
gw.wPolyline #([x,y,0],[x+w,y,0],[x+w,y+h,0],[x,y+h,0]) true
)
fibonacci_array[1] = 1  first 2 fibonacci numbers
fibonacci_array[2] = 1
gw.setColor #line orange
gw.wText ([4,30,0]) "fibonacci spiral" color:orange
drawQuad 0 0 1 1
drawQuad 1 0 1 1
for i = 3 to 12 do
(
fibonacci_array[i] = fibonacci_array[i1] + fibonacci_array[i2]
if i < w then
(
a = fibonacci_array[i]/2 as float
b = fibonacci_array[i1]/2 as float
c = fibonacci_array[i2]/2 as float
case of
(
(mod i 4 == 3): pos_Neu = [a+b,1*c,0]
(mod i 4 == 0): pos_Neu = [1*c,1*(a+b),0]
(mod i 4 == 1): pos_Neu = [1*(a+b),c,0]
(mod i 4 == 2): pos_Neu = [c,a+b,0]
)
position = pos_Alt + pos_Neu
drawQuad position.x position.y fibonacci_array[i] fibonacci_array[i]
pos_Alt = position
)
)
gw.enlargeUpdateRect #whole
gw.updateScreen()
)
CGTalk Moderation
01282009, 03:50 PM
This thread has been automatically closed as it remained inactive for 12 months. If you wish to continue the discussion, please create a new thread in the appropriate forum.