View Full Version : Problem with Variables

 davidbasalla08 August 2005, 04:49 PMHi, I just stumbled across this and cant seem to solve it... { float \$a1 = 1; float \$b = 0; \$i = 1; \$b = ("\$a" + \$i); } How would I do it so that ("\$a" + \$i) actually equals the value of \$a1? At the moment I just get: // Warning: line 8: Converting string "\$a1" to a float value of 0. // // Result: 0 // Any help would be appreciated! Cheers, Dave
AndersEgleus
08 August 2005, 05:19 PM
I don't really understand what it is you want to do.

the line

\$b = ("\$a" + \$i);

just tells maya to assign the string "\$a" plus the integer \$i (which has the value 0) to the variable \$b. Since \$b and \$i are numbers, the string "\$a" (note that "\$a" is a string, i.e. a piece of text and not a variable) must also be converted to a number - you can't (mathematically) add a number to a text, that's meaningless. Since maya has no clue what number the string "\$a" is supposed to mean, it automatically converts it to the number 0.0.

If you explain more clearly what you want to do we'll probably be able to help you.

davidbasalla
08 August 2005, 05:33 PM
i wanted to use the variable \$i to iterate through a bunch of variables (eg \$a1, \$a2, \$a3, \$a4,...)
so that if I say ("\$a" + \$i) (where \$i = 1, ,2 ,3, 4....) it returns the actual value of the variable \$a1 that I had declared previously...

so in my example (where it says
\$b = ("\$a" + \$i);
) I would like \$b to equal 1 (from my original declaration
float \$a1 = 1;
near the top)

so basically I want ("\$a" + \$i) to equal the variable \$a1
hmmm, its quite hard to explain, i hope this makes it a bit more clear?
Cheers Dave

08 August 2005, 05:34 PM
I think I know what you're trying to do. To make this work, you could use the following:

eval ("\$b = \$a" + \$i);

eval will take the created string ("\$b = \$a1") and evaluate it as MEL. This avoids the early interpretation that you're facing.

Does that help?

davidbasalla
08 August 2005, 05:45 PM
genius!
yeah, exactly what I wanted...
sorry for explaining it so badly...
Thanks alot!
Cheers, Dave

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08 August 2005, 05:45 PM
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