sutabi

10-04-2003, 09:09 AM

I am wanting a constant acceration no matter incline

The incline is 15 degree but I dont know it 15 degrees, the gravity is earth gravity and the mass is 1. The time interval = .1

I just take the current position - last stored position to find the x and y displacment

so the resulting force or net force = mass*gravity*(y/sqrt(x*x+y*y)

Note: (y/sqrt(x*x+y*y) = cos(theta)

so force = .855 and veloctiy (x axis) = .29

Now lets say I want velocity to be a constant 1.00

So displacment(x axis) = v/t = 1/.1 = 10

and I can't calculated acceration until the postions are stored

so A = final velocity - initial velocity/time interval

NOW! here where I am lost if I can figure the force needed for 15 degress and the velocity is .25 how do I figure out the force need to keep velocity at 1.00 with x degrees

The incline is 15 degree but I dont know it 15 degrees, the gravity is earth gravity and the mass is 1. The time interval = .1

I just take the current position - last stored position to find the x and y displacment

so the resulting force or net force = mass*gravity*(y/sqrt(x*x+y*y)

Note: (y/sqrt(x*x+y*y) = cos(theta)

so force = .855 and veloctiy (x axis) = .29

Now lets say I want velocity to be a constant 1.00

So displacment(x axis) = v/t = 1/.1 = 10

and I can't calculated acceration until the postions are stored

so A = final velocity - initial velocity/time interval

NOW! here where I am lost if I can figure the force needed for 15 degress and the velocity is .25 how do I figure out the force need to keep velocity at 1.00 with x degrees