simple selection

[dbiggs]

0.7% of 3054 is 21.38, not 2138.

that might e easier to select without losing count :)

[ewerybody]

{
int $all = 3054;
int $max = 2138;

int $randomNumberArray[];
int $count = 0;

int $rand;
for ($i = 1; $i <= $max; $i++)
{
$rand = rand(1,$all);
while(isInIntArray($rand,$randomNumberArray))
$rand = rand(1,$all);

$randomNumberArray[$count++] = $rand;
}

for ($i = 0; $i < $count; $i++)
print (($i + 1) + ": " + $randomNumberArray[$i] + "\n");
}

proc int isInIntArray(int $search, int $array[])
{
for ($item in $array)
if ($item == $search)
return 1;

return 0;
}

quite brute force but just now I couldn't think of another solution for it.

create random number array
loop your wanted count of random numbers from all cubes
create a random int from 1 to "number of all cubes"
while random int is not in random number array create new random int
write int to the random number array
print all ints from the array (or do what you want with it)
printing costs some time.. but selection would do as well.
have phun ;]

[Minael2008]

note: sorry for the terrible topic name. absent mindedly titled it and sent it off to the printing press: simple selection was a horrid title.

Thanks for the replies. i am using 3054 * .7 to get percentage. It is probably the wrong formula though.
thanks dbiggs.



ewerybody: thanks I will use this code, and I will send you the book. PMing you now. Thanks for your time, and much appreciated!

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