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AlexandreM
01-12-2009, 01:50 PM
I'm having an hard time to find the answer to this question that may be simple for some of you.

I want to find a way to draw a perfect square in perspective. I got the solution for those square defined with the 2 VP lines. But I can't find out about the squares that share a edge with the vertical line. With that perfect square, I'll then be able to build my perfect projected cube.

I would appreciate of someone could give me a simple method to find where to exactly place my green line in the attached picture.
c3n
01-13-2009, 10:30 AM
This might be what you're looking for:
http://www.sonjebasa.net/Instruction/2PtPerspective.pdf
(http://www.sonjebasa.net/Instruction/2PtPerspective.pdf)
mister3d
01-13-2009, 10:36 AM
Sorry, didn't het it right.
AlexandreM
01-13-2009, 06:49 PM
Thank you c3n, this is exactly what I was looking for! :-)
c3n
01-15-2009, 03:17 PM
Glad I could help :) I wonder if there's such a method for 3 point perspective, though.
AlexandreM
01-16-2009, 05:27 PM
Glad I could help :) I wonder if there's such a method for 3 point perspective, though.

From my understanding, its easier with 3 points perspective because there is a convergence of the vertical lines. You can then use their center points as a tool to find the exact edge height of the "perfect" square. Here is an example.
Advarsky
01-17-2009, 11:35 AM
c3n, thanks a lot man! Very useful info. :arteest:
And thanks to AlexandreM for the thread.
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