get only the trasnform node...

[Robert Bateman]

ls -type transform;

for all nodes derived from transform

or

ls -exactType transform;

for only transforms (ie, ignores joints, ik handles etc)

[mhovland]

You will have to use your selection that includes cameras, and then create a new array without the cameras.

Loop through your selection array and test each member using the nodeType command,

I will post an example when I get in to work.

[Robert Bateman]

sorry mis-read first time around.....


global proc string[] getXforms(string $fromType) {
$items = `ls -type $fromType`;
string $xforms[];
for( $i in $items ) {
$parents = `listRelatives -p $i`;
for($p in $parents) $xforms[size($xforms)]=$p;
}
return $xforms;
}


so now to get all transforms for a mesh you can do...

select -r `getXforms "mesh"`;

I guess for all dag objects excluding cameras you could do...



global proc string[] getXforms2() {
$items = `ls -dag`;
string $xforms[];
for( $i in $items ) {
if( "camera" != `nodeType $i`) {
$parents = `listRelatives -p $i`;
for($p in $parents) $xforms[size($xforms)]=$p;
}
}
return $xforms;
}

[mhovland]

Rob beat me to the code, and his is cooler than what I would have posted anyway.

[egf]

thanks, but if you run this code you geting a surprise,

//side is a dag camera you can test when front, top.
if("camera" == `nodeType side`) {print "Iam a camera node";}

else

{

if ("transform" == `nodeType side`) {print "Iam a transform node";}

};


any way thaks. I find a whorearound :).

[Robert Bateman]

what suprise would that be? A camera is only a shape that is parented under a transform (the same as every other dag object in Maya), so yes "side" is a transform which places the camera "sideShape" in the world. What's suprising about that? or have i missed something?

[egf]

My fault sorry
thaks

[CGTalk Moderation]

This thread has been automatically closed as it remained inactive for 12 months. If you wish to continue the discussion, please create a new thread in the appropriate forum.